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Popular Calculus >

integral of 16^x

Solution

\int 1 6^{x} d x

Solution

\frac{2 ^{4 x - 2}}{ln ( 2 )} + C

Solution steps

\int 1 6^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{1 6 ^{x}}{ln ( 16 )}

Simplify

\frac{1 6 ^{x}}{ln ( 16 )} : \frac{2 ^{4 x - 2}}{ln ( 2 )}

= \frac{2 ^{4 x - 2}}{ln ( 2 )}

Add a constant to the solution

= \frac{2 ^{4 x - 2}}{ln ( 2 )} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 16^x ?
The integral of 16^x is (2^{4x-2})/(ln(2))+C