What is the integral of ((x^7+1))/(sqrt(x^8+8x)) ?

The integral of ((x^7+1))/(sqrt(x^8+8x)) is 1/4 sqrt(x^8+8x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ((x^7+1))/(sqrt(x^8+8x))

\int \frac{( x ^{7} + 1 )}{x ^{8} + 8 x} d x

\frac{1}{4} x^{8} + 8 x + C

Solution steps

\int \frac{x ^{7} + 1}{x ^{8} + 8 x} d x

Apply u-substitution

= \int \frac{1}{8 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int \frac{1}{u} d u

Apply the Power Rule

= \frac{1}{8} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = x^{8} + 8 x

= \frac{1}{8} \cdot 2 (x^{8} + 8 x)^{\frac{1}{2}}

Simplify

\frac{1}{8} \cdot 2 (x^{8} + 8 x)^{\frac{1}{2}} : \frac{1}{4} x^{8} + 8 x

= \frac{1}{4} x^{8} + 8 x

Add a constant to the solution

= \frac{1}{4} x^{8} + 8 x + C

What is the integral of ((x^7+1))/(sqrt(x^8+8x)) ?
The integral of ((x^7+1))/(sqrt(x^8+8x)) is 1/4 sqrt(x^8+8x)+C