What is the integral of 18x^5-10x^4+12 ?

The integral of 18x^5-10x^4+12 is 3x^6-2x^5+12x+C

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integral of 18x^5-10x^4+12

\int 18 x^{5} - 10 x^{4} + 12 d x

3 x^{6} - 2 x^{5} + 12 x + C

Solution steps

\int 18 x^{5} - 10 x^{4} + 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 18 x^{5} d x - \int 10 x^{4} d x + \int 12 d x

\int 18 x^{5} d x = 3 x^{6}

\int 10 x^{4} d x = 2 x^{5}

\int 12 d x = 12 x

= 3 x^{6} - 2 x^{5} + 12 x

Add a constant to the solution

= 3 x^{6} - 2 x^{5} + 12 x + C

What is the integral of 18x^5-10x^4+12 ?
The integral of 18x^5-10x^4+12 is 3x^6-2x^5+12x+C