integral of 2sqrt(x^3)+7\sqrt[3]{x^2}

解答

\int 2 x^{3} + 7 3 x^{2} d x

\frac{4}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}} + C

求解步骤

\int 2 x^{3} + 7 3 x^{2} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x + \int 7 3 x^{2} d x

\int 2 x^{3} d x = \frac{4}{5} x^{\frac{5}{2}}

\int 7 3 x^{2} d x = \frac{21}{5} x^{\frac{5}{3}}

= \frac{4}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}}

解答补常数

= \frac{4}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}} + C

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