What is the integral of 10x(x^2+1)^4 ?

The integral of 10x(x^2+1)^4 is (x^2+1)^5+C

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integral of 10x(x^2+1)^4

\int 10 x (x^{2} + 1)^{4} d x

(x^{2} + 1)^{5} + C

Solution steps

\int 10 x (x^{2} + 1)^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x (x^{2} + 1)^{4} d x

Apply u-substitution

= 10 \cdot \int \frac{u ^{4}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{2} \cdot \int u^{4} d u

Apply the Power Rule

= 10 \cdot \frac{1}{2} \cdot \frac{u ^{5}}{5}

Substitute back

u = x^{2} + 1

= 10 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 1 ) ^{5}}{5}

Simplify

10 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 1 ) ^{5}}{5} : (x^{2} + 1)^{5}

= (x^{2} + 1)^{5}

Add a constant to the solution

= (x^{2} + 1)^{5} + C

What is the integral of 10x(x^2+1)^4 ?
The integral of 10x(x^2+1)^4 is (x^2+1)^5+C