What is the integral of (x^2-3x+1)cos(x) ?

The integral of (x^2-3x+1)cos(x) is x^2sin(x)-3xsin(x)+2xcos(x)-sin(x)-3cos(x)+C

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integral of (x^2-3x+1)cos(x)

\int (x^{2} - 3 x + 1) cos (x) d x

x^{2} sin (x) - 3 x sin (x) + 2 x cos (x) - sin (x) - 3 cos (x) + C

Solution steps

\int (x^{2} - 3 x + 1) cos (x) d x

Apply Integration By Parts

= (x^{2} - 3 x + 1) sin (x) - \int (2 x - 3) sin (x) d x

\int (2 x - 3) sin (x) d x = - cos (x) (2 x - 3) + 2 sin (x)

= (x^{2} - 3 x + 1) sin (x) - (- cos (x) (2 x - 3) + 2 sin (x))

Simplify

(x^{2} - 3 x + 1) sin (x) - (- cos (x) (2 x - 3) + 2 sin (x)) : x^{2} sin (x) - 3 x sin (x) + 2 x cos (x) - sin (x) - 3 cos (x)

= x^{2} sin (x) - 3 x sin (x) + 2 x cos (x) - sin (x) - 3 cos (x)

Add a constant to the solution

= x^{2} sin (x) - 3 x sin (x) + 2 x cos (x) - sin (x) - 3 cos (x) + C

What is the integral of (x^2-3x+1)cos(x) ?
The integral of (x^2-3x+1)cos(x) is x^2sin(x)-3xsin(x)+2xcos(x)-sin(x)-3cos(x)+C