What is the integral of (1-2x)^{10} ?

The integral of (1-2x)^{10} is -1/22 (1-2x)^{11}+C

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integral of (1-2x)^{10}

\int (1 - 2 x)^{10} d x

- \frac{1}{22} (1 - 2 x)^{11} + C

Solution steps

\int (1 - 2 x)^{10} d x

Apply u-substitution

= \int - \frac{u ^{10}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int u^{10} d u

Apply the Power Rule

= - \frac{1}{2} \cdot \frac{u ^{11}}{11}

Substitute back

u = 1 - 2 x

= - \frac{1}{2} \cdot \frac{( 1 - 2 x ) ^{11}}{11}

Simplify

- \frac{1}{2} \cdot \frac{( 1 - 2 x ) ^{11}}{11} : - \frac{1}{22} (1 - 2 x)^{11}

= - \frac{1}{22} (1 - 2 x)^{11}

Add a constant to the solution

= - \frac{1}{22} (1 - 2 x)^{11} + C

What is the integral of (1-2x)^{10} ?
The integral of (1-2x)^{10} is -1/22 (1-2x)^{11}+C