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Popular Calculus >

integral of (t-3)^3

Solution

\int (t - 3)^{3} d t

Solution

\frac{( t - 3 ) ^{4}}{4} + C

Solution steps

\int (t - 3)^{3} d t

Apply u-substitution

= \int u^{3} d u

Apply the Power Rule

= \frac{u ^{4}}{4}

Substitute back

u = t - 3

= \frac{( t - 3 ) ^{4}}{4}

Add a constant to the solution

= \frac{( t - 3 ) ^{4}}{4} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (t-3)^3 ?
The integral of (t-3)^3 is ((t-3)^4)/4+C