What is the integral of x^{1/4}+1 ?

The integral of x^{1/4}+1 is 4/5 x^{5/4}+x+C

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integral of x^{1/4}+1

\int x^{\frac{1}{4}} + 1 d x

\frac{4}{5} x^{\frac{5}{4}} + x + C

Solution steps

\int x^{\frac{1}{4}} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{1}{4}} d x + \int 1 d x

\int x^{\frac{1}{4}} d x = \frac{4}{5} x^{\frac{5}{4}}

\int 1 d x = x

= \frac{4}{5} x^{\frac{5}{4}} + x

Add a constant to the solution

= \frac{4}{5} x^{\frac{5}{4}} + x + C

What is the integral of x^{1/4}+1 ?
The integral of x^{1/4}+1 is 4/5 x^{5/4}+x+C