What is the integral of x^2(x^3+1)^{100} ?

The integral of x^2(x^3+1)^{100} is 1/303 (x^3+1)^{101}+C

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integral of x^2(x^3+1)^{100}

\int x^{2} (x^{3} + 1)^{100} d x

\frac{1}{303} (x^{3} + 1)^{101} + C

Solution steps

\int x^{2} (x^{3} + 1)^{100} d x

Apply u-substitution

= \int \frac{u ^{100}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u^{100} d u

Apply the Power Rule

= \frac{1}{3} \cdot \frac{u ^{101}}{101}

Substitute back

u = x^{3} + 1

= \frac{1}{3} \cdot \frac{( x ^{3} + 1 ) ^{101}}{101}

Simplify

\frac{1}{3} \cdot \frac{( x ^{3} + 1 ) ^{101}}{101} : \frac{1}{303} (x^{3} + 1)^{101}

= \frac{1}{303} (x^{3} + 1)^{101}

Add a constant to the solution

= \frac{1}{303} (x^{3} + 1)^{101} + C

What is the integral of x^2(x^3+1)^{100} ?
The integral of x^2(x^3+1)^{100} is 1/303 (x^3+1)^{101}+C