What is the integral of 4sqrt(x^3)+9\sqrt[3]{x^2} ?

The integral of 4sqrt(x^3)+9\sqrt[3]{x^2} is 8/5 x^{5/2}+27/5 x^{5/3}+C

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integral of 4sqrt(x^3)+9\sqrt[3]{x^2}

\frac{8}{5} x^{\frac{5}{2}} + \frac{27}{5} x^{\frac{5}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 4 x^{3} d x = \frac{8}{5} x^{\frac{5}{2}}

= \frac{8}{5} x^{\frac{5}{2}} + \frac{27}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{8}{5} x^{\frac{5}{2}} + \frac{27}{5} x^{\frac{5}{3}} + C

What is the integral of 4sqrt(x^3)+9\sqrt[3]{x^2} ?
The integral of 4sqrt(x^3)+9\sqrt[3]{x^2} is 8/5 x^{5/2}+27/5 x^{5/3}+C