What is the integral of (cos(x)-,x) ?

The integral of (cos(x)-,x) is sin(x)-,(x^2)/2+C

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integral of (cos(x)-,x)

\int (cos (x) -, x) d x

sin (x) -, \frac{x ^{2}}{2} + C

Solution steps

\int cos (x) -, x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x - \int, x d x

\int cos (x) d x = sin (x)

\int, x d x =, \frac{x ^{2}}{2}

= sin (x) -, \frac{x ^{2}}{2}

Add a constant to the solution

= sin (x) -, \frac{x ^{2}}{2} + C

What is the integral of (cos(x)-,x) ?
The integral of (cos(x)-,x) is sin(x)-,(x^2)/2+C