What is the integral of \sqrt[3]{x}-1/x ?

The integral of \sqrt[3]{x}-1/x is 3/4 x^{4/3}-ln|x|+C

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integral of \sqrt[3]{x}-1/x

\frac{3}{4} x^{\frac{4}{3}} - ln ∣ x ∣ + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int \frac{1}{x} d x = ln ∣ x ∣

= \frac{3}{4} x^{\frac{4}{3}} - ln ∣ x ∣

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} - ln ∣ x ∣ + C

What is the integral of \sqrt[3]{x}-1/x ?
The integral of \sqrt[3]{x}-1/x is 3/4 x^{4/3}-ln|x|+C