derivative f(x)=10x^3-20x+1/5

Lösung

ableitung von

f (x) = 10 x^{3} - 20 x + \frac{1}{5}

30 x^{2} - 20

Schritte zur Lösung

\frac{d}{d x} (10 x^{3} - 20 x + \frac{1}{5})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 x^{3}) - \frac{d}{d x} (20 x) + \frac{d}{d x} (\frac{1}{5})

\frac{d}{d x} (10 x^{3}) = 30 x^{2}

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (\frac{1}{5}) = 0

= 30 x^{2} - 20 + 0

Vereinfache

= 30 x^{2} - 20

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