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Popular Calculus >

integral of-1/(4x^2)

Solution

\int - \frac{1}{4 x ^{2}} d x

Solution

\frac{1}{4 x} + C

Solution steps

\int - \frac{1}{4 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{4} \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= - \frac{1}{4} (- \frac{1}{x})

Simplify

- \frac{1}{4} (- \frac{1}{x}) : \frac{1}{4 x}

= \frac{1}{4 x}

Add a constant to the solution

= \frac{1}{4 x} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of-1/(4x^2) ?
The integral of-1/(4x^2) is 1/(4x)+C