What is the integral of (h^2)/(sqrt(h)) ?

The integral of (h^2)/(sqrt(h)) is 2/5 h^{5/2}+C

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integral of (h^2)/(sqrt(h))

\int \frac{h ^{2}}{h} d h

\frac{2}{5} h^{\frac{5}{2}} + C

Solution steps

\int \frac{h ^{2}}{h} d h

Simplify

\frac{h ^{2}}{h} : h^{\frac{3}{2}}

= \int h^{\frac{3}{2}} d h

Apply the Power Rule

= \frac{2}{5} h^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{5} h^{\frac{5}{2}} + C

What is the integral of (h^2)/(sqrt(h)) ?
The integral of (h^2)/(sqrt(h)) is 2/5 h^{5/2}+C