integral of 3x-9

解答

\int 3 x - 9 d x

\frac{3 x ^{2}}{2} - 9 x + C

求解步骤

\int 3 x - 9 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int 9 d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 9 d x = 9 x

= \frac{3 x ^{2}}{2} - 9 x

解答补常数

= \frac{3 x ^{2}}{2} - 9 x + C

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