What is the integral of ((6+x^2)/x) ?

The integral of ((6+x^2)/x) is 6ln|x|+(x^2)/2+C

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integral of ((6+x^2)/x)

\int (\frac{6 + x ^{2}}{x}) d x

6 ln ∣ x ∣ + \frac{x ^{2}}{2} + C

Solution steps

\int \frac{6 + x ^{2}}{x} d x

Expand

\frac{6 + x ^{2}}{x} : \frac{6}{x} + x

= \int \frac{6}{x} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{x} d x + \int x d x

\int \frac{6}{x} d x = 6 ln ∣ x ∣

\int x d x = \frac{x ^{2}}{2}

= 6 ln ∣ x ∣ + \frac{x ^{2}}{2}

Add a constant to the solution

= 6 ln ∣ x ∣ + \frac{x ^{2}}{2} + C

What is the integral of ((6+x^2)/x) ?
The integral of ((6+x^2)/x) is 6ln|x|+(x^2)/2+C