What is the integral of 4/((x^2+1)) ?

The integral of 4/((x^2+1)) is 4arctan(x)+C

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integral of 4/((x^2+1))

\int \frac{4}{( x ^{2} + 1 )} d x

4 arctan (x) + C

Solution steps

\int \frac{4}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 4 arctan (x)

Add a constant to the solution

= 4 arctan (x) + C

What is the integral of 4/((x^2+1)) ?
The integral of 4/((x^2+1)) is 4arctan(x)+C