What is the integral of ((x^3+3x^6))/(x^4) ?

The integral of ((x^3+3x^6))/(x^4) is ln|x|+x^3+C

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integral of ((x^3+3x^6))/(x^4)

\int \frac{( x ^{3} + 3 x ^{6} )}{x ^{4}} d x

ln ∣ x ∣ + x^{3} + C

Solution steps

\int \frac{x ^{3} + 3 x ^{6}}{x ^{4}} d x

Expand

\frac{x ^{3} + 3 x ^{6}}{x ^{4}} : \frac{1}{x} + 3 x^{2}

= \int \frac{1}{x} + 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int 3 x^{2} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int 3 x^{2} d x = x^{3}

= ln ∣ x ∣ + x^{3}

Add a constant to the solution

= ln ∣ x ∣ + x^{3} + C

What is the integral of ((x^3+3x^6))/(x^4) ?
The integral of ((x^3+3x^6))/(x^4) is ln|x|+x^3+C