What is the integral of (5-2x)^7 ?

The integral of (5-2x)^7 is -1/16 (5-2x)^8+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (5-2x)^7

\int (5 - 2 x)^{7} d x

- \frac{1}{16} (5 - 2 x)^{8} + C

Solution steps

\int (5 - 2 x)^{7} d x

Apply u-substitution

= \int - \frac{u ^{7}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int u^{7} d u

Apply the Power Rule

= - \frac{1}{2} \cdot \frac{u ^{8}}{8}

Substitute back

u = 5 - 2 x

= - \frac{1}{2} \cdot \frac{( 5 - 2 x ) ^{8}}{8}

Simplify

- \frac{1}{2} \cdot \frac{( 5 - 2 x ) ^{8}}{8} : - \frac{1}{16} (5 - 2 x)^{8}

= - \frac{1}{16} (5 - 2 x)^{8}

Add a constant to the solution

= - \frac{1}{16} (5 - 2 x)^{8} + C