What is the integral of ((x^2e^{-x}+x))/(x^2) ?

The integral of ((x^2e^{-x}+x))/(x^2) is -e^{-x}+ln|x|+C

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integral of ((x^2e^{-x}+x))/(x^2)

\int \frac{( x ^{2} e ^{- x} + x )}{x ^{2}} d x

- e^{- x} + ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{2} e ^{- x} + x}{x ^{2}} d x

Expand

\frac{x ^{2} e ^{- x} + x}{x ^{2}} : e^{- x} + \frac{1}{x}

= \int e^{- x} + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{- x} d x + \int \frac{1}{x} d x

\int e^{- x} d x = - e^{- x}

\int \frac{1}{x} d x = ln ∣ x ∣

= - e^{- x} + ln ∣ x ∣

Add a constant to the solution

= - e^{- x} + ln ∣ x ∣ + C

What is the integral of ((x^2e^{-x}+x))/(x^2) ?
The integral of ((x^2e^{-x}+x))/(x^2) is -e^{-x}+ln|x|+C