What is the integral of (ln^8(z))/z ?

The integral of (ln^8(z))/z is (ln^9(z))/9+C

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integral of (ln^8(z))/z

\int \frac{ln ^{8} ( z )}{z} d z

\frac{ln ^{9} ( z )}{9} + C

Solution steps

\int \frac{ln ^{8} ( z )}{z} d z

Apply u-substitution

= \int u^{8} d u

Apply the Power Rule

= \frac{u ^{9}}{9}

Substitute back

u = ln (z)

= \frac{ln ^{9} ( z )}{9}

Add a constant to the solution

= \frac{ln ^{9} ( z )}{9} + C

What is the integral of (ln^8(z))/z ?
The integral of (ln^8(z))/z is (ln^9(z))/9+C