What is the integral of 18(3x+2)^2 ?

The integral of 18(3x+2)^2 is 18(3x^3+6x^2+4x)+C

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integral of 18(3x+2)^2

\int 18 (3 x + 2)^{2} d x

18 (3 x^{3} + 6 x^{2} + 4 x) + C

Solution steps

\int 18 (3 x + 2)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int (3 x + 2)^{2} d x

Expand

(3 x + 2)^{2} : 9 x^{2} + 12 x + 4

= 18 \cdot \int 9 x^{2} + 12 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 18 (\int 9 x^{2} d x + \int 12 x d x + \int 4 d x)

\int 9 x^{2} d x = 3 x^{3}

\int 12 x d x = 6 x^{2}

\int 4 d x = 4 x

= 18 (3 x^{3} + 6 x^{2} + 4 x)

Add a constant to the solution

= 18 (3 x^{3} + 6 x^{2} + 4 x) + C

What is the integral of 18(3x+2)^2 ?
The integral of 18(3x+2)^2 is 18(3x^3+6x^2+4x)+C