What is the integral of (sin^2(x))/(1+sin(x)) ?

The integral of (sin^2(x))/(1+sin(x)) is -2/(tan(x/2)+1)-cos(x)-x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (sin^2(x))/(1+sin(x))

\int \frac{sin ^{2} ( x )}{1 + sin ( x )} d x

- \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x + C

Solution steps

\int \frac{sin ^{2} ( x )}{1 + sin ( x )} d x

Rewrite using trig identities

= \int \frac{1 - cos ^{2} ( x )}{1 + sin ( x )} d x

Expand

\frac{1 - cos ^{2} ( x )}{1 + sin ( x )} : \frac{1}{1 + sin ( x )} - \frac{cos ^{2} ( x )}{1 + sin ( x )}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{1 + sin ( x )} d x - \int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x

\int \frac{1}{1 + sin ( x )} d x = - \frac{2}{tan ( \frac{x}{2} ) + 1}

\int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x = cos (x) + x

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - (cos (x) + x)

Simplify

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x

Add a constant to the solution

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x + C

What is the integral of (sin^2(x))/(1+sin(x)) ?
The integral of (sin^2(x))/(1+sin(x)) is -2/(tan(x/2)+1)-cos(x)-x+C