What is the integral of e^{8x-8} ?

The integral of e^{8x-8} is 1/8 e^{8x-8}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of e^{8x-8}

\int e^{8 x - 8} d x

\frac{1}{8} e^{8 x - 8} + C

Solution steps

\int e^{8 x - 8} d x

Apply u-substitution

= \int e^{u} \frac{1}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{8} e^{u}

Substitute back

u = 8 x - 8

= \frac{1}{8} e^{8 x - 8}

Add a constant to the solution

= \frac{1}{8} e^{8 x - 8} + C