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x^3y^{'''}+xy^'-y=0

解答

x^{3} y^{^{'''}} + x y^{^{'}} - y = 0

解答

y = c_{1} x + c_{2} ln (x) x + c_{3} ln^{2} (x) x

求解步骤

x^{3} y^{'''} (x) + x y^{'} (x) - y = 0

求解线性方程:

y = c_{1} x + c_{2} ln (x) x + c_{3} ln^{2} (x) x

y = c_{1} x + c_{2} ln (x) x + c_{3} ln^{2} (x) x

作图

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