What is the integral of e^{7t+1} ?

The integral of e^{7t+1} is 1/7 e^{7t+1}+C

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integral of e^{7t+1}

\int e^{7 t + 1} d t

\frac{1}{7} e^{7 t + 1} + C

Solution steps

\int e^{7 t + 1} d t

Apply u-substitution

= \int e^{u} \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{7} e^{u}

Substitute back

u = 7 t + 1

= \frac{1}{7} e^{7 t + 1}

Add a constant to the solution

= \frac{1}{7} e^{7 t + 1} + C