What is the integral of 2x+5/(2x^2) ?

The integral of 2x+5/(2x^2) is x^2-5/(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2x+5/(2x^2)

\int 2 x + \frac{5}{2 x ^{2}} d x

x^{2} - \frac{5}{2 x} + C

Solution steps

\int 2 x + \frac{5}{2 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x + \int \frac{5}{2 x ^{2}} d x

\int 2 x d x = x^{2}

\int \frac{5}{2 x ^{2}} d x = - \frac{5}{2 x}

= x^{2} - \frac{5}{2 x}

Add a constant to the solution

= x^{2} - \frac{5}{2 x} + C

What is the integral of 2x+5/(2x^2) ?
The integral of 2x+5/(2x^2) is x^2-5/(2x)+C