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tangent y= 1/(x-1),\at x=6

解答

切线

y = \frac{1}{x - 1}, at x = 6

解答

y = - \frac{1}{25} x + \frac{11}{25}

求解步骤

找到切点:

(6, \frac{1}{5})

计算

y = \frac{1}{x - 1}

的斜率:

\frac{d y}{d x} = - \frac{1}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{25}

找到斜率 m=

- \frac{1}{25}

且穿过

(6, \frac{1}{5})

的直线:

y = - \frac{1}{25} x + \frac{11}{25}

y = - \frac{1}{25} x + \frac{11}{25}

作图

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