What is the integral of (x^5+x^3+2)/(1+x^2) ?

The integral of (x^5+x^3+2)/(1+x^2) is (x^4)/4+2arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x^5+x^3+2)/(1+x^2)

\int \frac{x ^{5} + x ^{3} + 2}{1 + x ^{2}} d x

\frac{x ^{4}}{4} + 2 arctan (x) + C

Solution steps

\int \frac{x ^{5} + x ^{3} + 2}{1 + x ^{2}} d x

Long division

\frac{x ^{5} + x ^{3} + 2}{1 + x ^{2}} : x^{3} + \frac{2}{x ^{2} + 1}

= \int x^{3} + \frac{2}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int \frac{2}{x ^{2} + 1} d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int \frac{2}{x ^{2} + 1} d x = 2 arctan (x)

= \frac{x ^{4}}{4} + 2 arctan (x)

Add a constant to the solution

= \frac{x ^{4}}{4} + 2 arctan (x) + C

What is the integral of (x^5+x^3+2)/(1+x^2) ?
The integral of (x^5+x^3+2)/(1+x^2) is (x^4)/4+2arctan(x)+C