What is the integral of (cos(2x))/(sin^4(2x)) ?

The integral of (cos(2x))/(sin^4(2x)) is -1/6 csc^3(2x)+C

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integral of (cos(2x))/(sin^4(2x))

\int \frac{cos ( 2 x )}{sin ^{4} ( 2 x )} d x

- \frac{1}{6} csc^{3} (2 x) + C

Solution steps

\int \frac{cos ( 2 x )}{sin ^{4} ( 2 x )} d x

Apply u-substitution

= \int \frac{cos ( u )}{2 sin ^{4} ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{cos ( u )}{sin ^{4} ( u )} d u

Apply u-substitution

= \frac{1}{2} \cdot \int \frac{1}{v ^{4}} d v

Apply the Power Rule

= \frac{1}{2} (- \frac{1}{3 v ^{3}})

Substitute back

= \frac{1}{2} (- \frac{1}{3 sin ^{3} ( 2 x )})

Simplify

\frac{1}{2} (- \frac{1}{3 sin ^{3} ( 2 x )}) : - \frac{1}{6} csc^{3} (2 x)

= - \frac{1}{6} csc^{3} (2 x)

Add a constant to the solution

= - \frac{1}{6} csc^{3} (2 x) + C

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What is the integral of (cos(2x))/(sin^4(2x)) ?
The integral of (cos(2x))/(sin^4(2x)) is -1/6 csc^3(2x)+C