What is the integral of (200)/((x+2)^2) ?

The integral of (200)/((x+2)^2) is -(200)/(x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (200)/((x+2)^2)

\int \frac{200}{( x + 2 ) ^{2}} d x

- \frac{200}{x + 2} + C

Solution steps

\int \frac{200}{( x + 2 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 200 \cdot \int \frac{1}{( x + 2 ) ^{2}} d x

Apply u-substitution

= 200 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= 200 (- \frac{1}{u})

Substitute back

u = x + 2

= 200 (- \frac{1}{x + 2})

Simplify

200 (- \frac{1}{x + 2}) : - \frac{200}{x + 2}

= - \frac{200}{x + 2}

Add a constant to the solution

= - \frac{200}{x + 2} + C

What is the integral of (200)/((x+2)^2) ?
The integral of (200)/((x+2)^2) is -(200)/(x+2)+C