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Popular Calculus >

integral of 1/(xx+1)

Solution

\int \frac{1}{xx + 1} d x

Solution

arctan (x) + C

Solution steps

\int \frac{1}{xx + 1} d x

xx = x^{2}

= \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1/(xx+1) ?
The integral of 1/(xx+1) is arctan(x)+C