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Popular Calculus >

integral of x(x-9)

Solution

\int x (x - 9) d x

Solution

\frac{x ^{3}}{3} - \frac{9 x ^{2}}{2} + C

Solution steps

\int x (x - 9) d x

Expand

x (x - 9) : x^{2} - 9 x

= \int x^{2} - 9 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 9 x d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 9 x d x = \frac{9 x ^{2}}{2}

= \frac{x ^{3}}{3} - \frac{9 x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{9 x ^{2}}{2} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of x(x-9) ?
The integral of x(x-9) is (x^3)/3-(9x^2)/2+C