What is the integral of sin(5x)e^{3x} ?

The integral of sin(5x)e^{3x} is -(5e^{3x}cos(5x))/(34)+(3e^{3x}sin(5x))/(34)+C

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integral of sin(5x)e^{3x}

\int sin (5 x) e^{3 x} d x

- \frac{5 e ^{3 x} cos ( 5 x )}{34} + \frac{3 e ^{3 x} sin ( 5 x )}{34} + C

Solution steps

\int sin (5 x) e^{3 x} d x

Apply Integration By Parts

= - \frac{1}{5} e^{3 x} cos (5 x) - \int - \frac{3}{5} e^{3 x} cos (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} e^{3 x} cos (5 x) - (- \frac{3}{5} \cdot \int e^{3 x} cos (5 x) d x)

Apply Integration By Parts

= - \frac{1}{5} e^{3 x} cos (5 x) - (- \frac{3}{5} (\frac{1}{5} e^{3 x} sin (5 x) - \int \frac{3}{5} e^{3 x} sin (5 x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} e^{3 x} cos (5 x) - (- \frac{3}{5} (\frac{1}{5} e^{3 x} sin (5 x) - \frac{3}{5} \cdot \int e^{3 x} sin (5 x) d x))

Therefore

\int e^{3 x} sin (5 x) d x = - \frac{1}{5} e^{3 x} cos (5 x) - (- \frac{3}{5} (\frac{1}{5} e^{3 x} sin (5 x) - \frac{3}{5} \cdot \int e^{3 x} sin (5 x) d x))

Isolate

\int e^{3 x} sin (5 x) d x

= - \frac{5 e ^{3 x} cos ( 5 x )}{34} + \frac{3 e ^{3 x} sin ( 5 x )}{34}

Add a constant to the solution

= - \frac{5 e ^{3 x} cos ( 5 x )}{34} + \frac{3 e ^{3 x} sin ( 5 x )}{34} + C

What is the integral of sin(5x)e^{3x} ?
The integral of sin(5x)e^{3x} is -(5e^{3x}cos(5x))/(34)+(3e^{3x}sin(5x))/(34)+C