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Popular Calculus >

integral of 4-t

Solution

\int 4 - t d t

Solution

4 t - \frac{t ^{2}}{2} + C

Solution steps

\int 4 - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d t - \int t d t

\int 4 d t = 4 t

\int t d t = \frac{t ^{2}}{2}

= 4 t - \frac{t ^{2}}{2}

Add a constant to the solution

= 4 t - \frac{t ^{2}}{2} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 4-t ?
The integral of 4-t is 4t-(t^2)/2+C