What is the integral of (-2x)/(e^x) ?

The integral of (-2x)/(e^x) is -2(-x/(e^x)-1/(e^x))+C

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integral of (-2x)/(e^x)

\int \frac{- 2 x}{e ^{x}} d x

- 2 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}}) + C

Solution steps

\int \frac{- 2 x}{e ^{x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{x}{e ^{x}} d x

Apply Integration By Parts

= - 2 (- \frac{x}{e ^{x}} - \int - \frac{1}{e ^{x}} d x)

\int - \frac{1}{e ^{x}} d x = \frac{1}{e ^{x}}

= - 2 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}})

Add a constant to the solution

= - 2 (- \frac{x}{e ^{x}} - \frac{1}{e ^{x}}) + C

What is the integral of (-2x)/(e^x) ?
The integral of (-2x)/(e^x) is -2(-x/(e^x)-1/(e^x))+C