What is the integral of (e^x)/(ln(2)) ?

The integral of (e^x)/(ln(2)) is 1/(ln(2))e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (e^x)/(ln(2))

\int \frac{e ^{x}}{ln ( 2 )} d x

\frac{1}{ln ( 2 )} e^{x} + C

Solution steps

\int \frac{e ^{x}}{ln ( 2 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{ln ( 2 )} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= \frac{1}{ln ( 2 )} e^{x}

Add a constant to the solution

= \frac{1}{ln ( 2 )} e^{x} + C

What is the integral of (e^x)/(ln(2)) ?
The integral of (e^x)/(ln(2)) is 1/(ln(2))e^x+C