What is the integral of x/(sqrt(4+x)) ?

The integral of x/(sqrt(4+x)) is 2(1/3 (4+x)^{3/2}-4sqrt(4+x))+C

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integral of x/(sqrt(4+x))

\int \frac{x}{4 + x} d x

2 (\frac{1}{3} (4 + x)^{\frac{3}{2}} - 4 4 + x) + C

Solution steps

\int \frac{x}{4 + x} d x

Apply u-substitution

= \int 2 (u^{2} - 4) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int u^{2} - 4 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{2} d u - \int 4 d u)

\int u^{2} d u = \frac{u ^{3}}{3}

\int 4 d u = 4 u

= 2 (\frac{u ^{3}}{3} - 4 u)

Substitute back

u = 4 + x

= 2 (\frac{( 4 + x ) ^{3}}{3} - 4 4 + x)

Simplify

2 (\frac{( 4 + x ) ^{3}}{3} - 4 4 + x) : 2 (\frac{1}{3} (4 + x)^{\frac{3}{2}} - 4 4 + x)

= 2 (\frac{1}{3} (4 + x)^{\frac{3}{2}} - 4 4 + x)

Add a constant to the solution

= 2 (\frac{1}{3} (4 + x)^{\frac{3}{2}} - 4 4 + x) + C

What is the integral of x/(sqrt(4+x)) ?
The integral of x/(sqrt(4+x)) is 2(1/3 (4+x)^{3/2}-4sqrt(4+x))+C