What is the integral of 1/(x*sqrt(x^2-2)) ?

The integral of 1/(x*sqrt(x^2-2)) is 1/(sqrt(2))arcsec(1/(sqrt(2))x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(x*sqrt(x^2-2))

\int \frac{1}{x \cdot x ^{2} - 2} d x

\frac{1}{2} arcsec (\frac{1}{2} x) + C

Solution steps

\int \frac{1}{x x ^{2} - 2} d x

Apply Trigonometric Substitution

= \int \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 d u

Integral of a constant:

\int a d x = a x

= \frac{1}{2} \cdot 1 \cdot u

Substitute back

u = arcsec (\frac{1}{2} x)

= \frac{1}{2} \cdot 1 \cdot arcsec (\frac{1}{2} x)

Simplify

= \frac{1}{2} arcsec (\frac{1}{2} x)

Add a constant to the solution

= \frac{1}{2} arcsec (\frac{1}{2} x) + C

What is the integral of 1/(x*sqrt(x^2-2)) ?
The integral of 1/(x*sqrt(x^2-2)) is 1/(sqrt(2))arcsec(1/(sqrt(2))x)+C