What is the integral of 1/(12x^6) ?

The integral of 1/(12x^6) is -1/(60x^5)+C

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integral of 1/(12x^6)

\int \frac{1}{12 x ^{6}} d x

- \frac{1}{60 x ^{5}} + C

Solution steps

\int \frac{1}{12 x ^{6}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int \frac{1}{x ^{6}} d x

Apply the Power Rule

= \frac{1}{12} (- \frac{1}{5 x ^{5}})

Simplify

\frac{1}{12} (- \frac{1}{5 x ^{5}}) : - \frac{1}{60 x ^{5}}

= - \frac{1}{60 x ^{5}}

Add a constant to the solution

= - \frac{1}{60 x ^{5}} + C