What is the integral of x/3 e^{2x} ?

The integral of x/3 e^{2x} is 1/12 (2e^{2x}x-e^{2x})+C

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integral of x/3 e^{2x}

\int \frac{x}{3} e^{2 x} d x

\frac{1}{12} (2 e^{2 x} x - e^{2 x}) + C

Solution steps

\int \frac{x}{3} e^{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int x e^{2 x} d x

Apply u-substitution

= \frac{1}{3} \cdot \int \frac{e ^{u} u}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \frac{1}{4} \cdot \int e^{u} u d u

Apply Integration By Parts

= \frac{1}{3} \cdot \frac{1}{4} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{3} \cdot \frac{1}{4} (e^{u} u - e^{u})

Substitute back

u = 2 x

= \frac{1}{3} \cdot \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

Simplify

\frac{1}{3} \cdot \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) : \frac{1}{12} (2 e^{2 x} x - e^{2 x})

= \frac{1}{12} (2 e^{2 x} x - e^{2 x})

Add a constant to the solution

= \frac{1}{12} (2 e^{2 x} x - e^{2 x}) + C

What is the integral of x/3 e^{2x} ?
The integral of x/3 e^{2x} is 1/12 (2e^{2x}x-e^{2x})+C