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Popular Calculus >

integral from 0 to 1 of x(x+1/2)

Solution

\int_{0}^{1} x (x + \frac{1}{2}) d x

Solution

\frac{7}{12}

+1

Decimal

0.58333 \dots

Solution steps

\int_{0}^{1} x (x + \frac{1}{2}) d x

Expand

x (x + \frac{1}{2}) : x^{2} + \frac{x}{2}

= \int_{0}^{1} x^{2} + \frac{x}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} \frac{x}{2} d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} \frac{x}{2} d x = \frac{1}{4}

= \frac{1}{3} + \frac{1}{4}

Simplify

\frac{1}{3} + \frac{1}{4} : \frac{7}{12}

= \frac{7}{12}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of x(x+1/2) ?
The integral from 0 to 1 of x(x+1/2) is 7/12