What is the integral from 0 to 3 of xe^{x^2} ?

The integral from 0 to 3 of xe^{x^2} is (e^9-1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 3 of xe^{x^2}

\int_{0}^{3} x e^{x^{2}} d x

\frac{e ^{9} - 1}{2}

Decimal

4051.04196 \dots

Solution steps

\int_{0}^{3} x e^{x^{2}} d x

Apply u-substitution

= \int_{0}^{9} \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{9} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} [e^{u}]_{0}^{9}

Compute the boundaries:

e^{9} - 1

= \frac{1}{2} (e^{9} - 1)

Simplify

= \frac{e ^{9} - 1}{2}

What is the integral from 0 to 3 of xe^{x^2} ?
The integral from 0 to 3 of xe^{x^2} is (e^9-1)/2