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Popular Calculus >

integral from 2 to 4 of (x^2-4)

Solution

\int_{2}^{4} (x^{2} - 4) d x

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

\int_{2}^{4} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} x^{2} d x - \int_{2}^{4} 4 d x

\int_{2}^{4} x^{2} d x = \frac{56}{3}

\int_{2}^{4} 4 d x = 8

= \frac{56}{3} - 8

Simplify

\frac{56}{3} - 8 : \frac{32}{3}

= \frac{32}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 2 to 4 of (x^2-4) ?
The integral from 2 to 4 of (x^2-4) is 32/3