integral from 0 to 2 of (x-1)

Lösung

\int_{0}^{2} (x - 1) d x

0

Schritte zur Lösung

\int_{0}^{2} x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d x - \int_{0}^{2} 1 d x

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= 2 - 2

Vereinfache

= 0

\int_{1}^{2} (4 x^{3} - 3 x^{2} + 2) d x

\int_{2}^{3} \frac{x + 1}{x} d x

\int_{0}^{5} (x^{2} + 1) d x

\int_{2}^{8} x^{2} d x

\int_{0}^{1} x^{5} 1 - x^{6} d x