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Popular Calculus >

integral from-4 to 4 of |x^2-9|

Solution

\int_{- 4}^{4} x^{2} - 9 d x

Solution

\frac{128}{3}

+1

Decimal

42.66666 \dots

Solution steps

\int_{- 4}^{4} x^{2} - 9 d x

Eliminate Absolutes

= \int_{- 4}^{- 3} x^{2} - 9 d x + \int_{- 3}^{3} - x^{2} + 9 d x + \int_{3}^{4} x^{2} - 9 d x

\int_{- 4}^{- 3} x^{2} - 9 d x = \frac{10}{3}

\int_{- 3}^{3} - x^{2} + 9 d x = 36

\int_{3}^{4} x^{2} - 9 d x = \frac{10}{3}

= \frac{10}{3} + 36 + \frac{10}{3}

Simplify

\frac{10}{3} + 36 + \frac{10}{3} : \frac{128}{3}

= \frac{128}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-4 to 4 of |x^2-9| ?
The integral from-4 to 4 of |x^2-9| is 128/3