What is the integral from 0 to 1 of (x^{17}+17^x) ?

The integral from 0 to 1 of (x^{17}+17^x) is 1/18+(16)/(ln(17))

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integral from 0 to 1 of (x^{17}+17^x)

\int_{0}^{1} (x^{17} + 1 7^{x}) d x

\frac{1}{18} + \frac{16}{ln ( 17 )}

Decimal

5.70285 \dots

Solution steps

\int_{0}^{1} x^{17} + 1 7^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{17} d x + \int_{0}^{1} 1 7^{x} d x

\int_{0}^{1} x^{17} d x = \frac{1}{18}

\int_{0}^{1} 1 7^{x} d x = \frac{16}{ln ( 17 )}

= \frac{1}{18} + \frac{16}{ln ( 17 )}

What is the integral from 0 to 1 of (x^{17}+17^x) ?
The integral from 0 to 1 of (x^{17}+17^x) is 1/18+(16)/(ln(17))