What is the integral from 0 to pi/2 of (x-sin(x)) ?

The integral from 0 to pi/2 of (x-sin(x)) is (pi^2)/8-1

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integral from 0 to pi/2 of (x-sin(x))

\int_{0}^{\frac{π}{2}} (x - sin (x)) d x

\frac{π ^{2}}{8} - 1

Decimal

0.23370 \dots

Solution steps

\int_{0}^{\frac{π}{2}} x - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} x d x - \int_{0}^{\frac{π}{2}} sin (x) d x

\int_{0}^{\frac{π}{2}} x d x = \frac{π ^{2}}{8}

\int_{0}^{\frac{π}{2}} sin (x) d x = 1

= \frac{π ^{2}}{8} - 1

What is the integral from 0 to pi/2 of (x-sin(x)) ?
The integral from 0 to pi/2 of (x-sin(x)) is (pi^2)/8-1